DSA for Friday, 25-July-2025

[Shivam joshi]

Solution of question 2

#include <stdio.h>

int main() {

int n, i, term, sum = 0;

// Ask user for number of terms

printf("Enter the number of terms: ");

scanf("%d", &n);

printf("Series: ");

for(i = 1; i <= n; i++) {

// Term is 1 for odd positions, -1 for even positions

if(i % 2 == 1)

term = 1;

else

term = -1;

printf("%d", term);

if(i != n) {

printf(", ");

}

sum += term;

}

printf("\nSum of the series: %d\n", sum);

return 0;

}

[Shivam joshi]

#include <stdio.h>

int main() {

int n, i;

int sum_natural = 0, sum_odd = 0, sum_even = 0;

printf("Enter the number of terms: ");

scanf("%d", &n);

// Natural numbers

printf("\nNatural Numbers Series: ");

for(i = 1; i <= n; i++) {

printf("%d ", i);

sum_natural += i;

}

printf("\nSum of Natural Numbers: %d\n", sum_natural);

// Odd numbers

printf("\nOdd Numbers Series: ");

for(i = 0; i < n; i++) {

int odd = 2 * i + 1;

printf("%d ", odd);

sum_odd += odd;

}

printf("\nSum of Odd Numbers: %d\n", sum_odd);

// Even numbers

printf("\nEven Numbers Series: ");

for(i = 0; i < n; i++) {

int even = 2 * i;

printf("%d ", even);

sum_even += even;

}

printf("\nSum of Even Numbers: %d\n", sum_even);

return 0;

}